Theorem. let $S$ be a semigroup then its algebraic $J$ preorder $\subseteq$ is a directed preorder, which means that every two elements $a$ and $b$ have an upper bound.
Proof. let $a,b \in S$ then we can construct an upper bound by $ab$ $\square$
Corollary. every J-trivial semigroup is a directed poset.
Directed posets can be seen to be the posets that have some kind of compositional process associated to them, even if that compositional process is not a semilattice. Upper bounds correspond to the composition of elements.
Example. the free non-commutative semigroup $S$ on a set of generators $X$ is a J-trivial semigroup, whose partial ordering is the consecutive subsequence ordering. This is not a semilattice, but it is directed because any two words have an upper bound provided by their composition.
The example of the free non-commutative semigroup should demonstrate that $L$ and $R$ preorders are not directed in general, even though $J$ is. The prefix and postfix orderings on the free non-commutative semigroups are trees, so elements don't have an upper bound unless they are comparable. There is also the example of a pure rectangular band, which has one of its $L$ or $R$ preorders an antichain.
The reason every pair of elements in a semigroup has an upper bound, is every element has a composition that exists. It follows that in a partial semigroup such as a category, its preorder need not be directed. Morphisms in different connected components don't need to have an upper bound.
- The $L$ and $R$ preorders of a semigroup need not be directed.
- The morphism preorder of a category need not be directed.
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