- Lattices of normal subgroups
- Lattices of submodules
- Lattices of ideals of a ring
- Lattices of normal intermediate field extensions of galois extensions
Proposition. the lattice of normal intermediate field extensions of a galois extension form a modular lattice
Proof. the lattice of normal subgroups of the galois group of the field extension is modular. By the fundamental theorem of galois theory (FTGT), we know that the lattice of normal intermediate field extensions of a galois extension is order-dual to the lattice of normal subgroups. But since modularity is a self-dual condition, the lattice of normal intermediate field extensions is modular.
Subalgebra-modular structures:
Supposing that we have an algebraic structure like a ring then we can form from these structures subalgebra systems (suborders of Sub(A)) that are modular. A separate question is under what conditions is Sub(A) modular? We can now answer this to some extent using the concepts already covered. Here are algebraic structures for which Sub(A) is modular:
- Dedekind groups
- Commutative groups (a special case of dedekind groups)
- Modules
- Fields which are galois-dedekind over their prime subfield
- The ring of integers Z (all subrings are ideals)
Complements:
Most of these subalgebras are related normal subgroups in some way, but normal subgroups have another important property. In the lattice of normal subgroups, complementary members characterize direct product representations of the group. It is not hard to see then, how complements are unordered, as a given subgroup which characterizes the group by direct product with some other complementary subgroup is not going to produce the same direct product with a subalgebra of that other complementary group. Therefore, the property that complements in a modular lattice are unordered (which was proven entirely using order theory) is a pre-requisite for the complements to determine direct products.
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